x^2+169=26x

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Solution for x^2+169=26x equation: 



x^2+169=26x

We move all terms to the left:

x^2+169-(26x)=0

a = 1; b = -26; c = +169;
Δ = b2-4ac
Δ = -262-4·1·169
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{26}{2}=13$

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